In a geometric progression, the first term is 153 and the sixth term is \(\frac{17}{27}\). The sum of the first four terms is
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Correct Answer: Option B
Explanation:
a = 153 - 1st term, 6th term = \(\frac{17}{27}\)
nth term = arn
Sn = a(1 - rn) where r < 1
6th term = 153\(\frac{1 - 0.4^4}{1 - 0.4}\)
= \(\frac{680}{3}\)
a = 153 - 1st term, 6th term = \(\frac{17}{27}\)
nth term = arn
Sn = a(1 - rn) where r < 1
6th term = 153\(\frac{1 - 0.4^4}{1 - 0.4}\)
= \(\frac{680}{3}\)