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If sec2 \(\theta\) + tan2 \(\theta\) = 3, then the angle \(\theta\) is equal to

If sec2 \(\theta\) + tan2 \(\theta\) = 3, then the angle \(\theta\) is equal to
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  • A 30o
  • B 45o
  • C 60o
  • D 90o
  • E 105o
Correct Answer: Option B
Explanation:
sec2 \(\theta\) + tan2 \(\theta\) = 3
but tan2 \(\theta\) = 1 + sec2 \(\theta\)
1 + tan2 \(\theta\) + tan2 \(\theta\) = 3
2 tan2 \(\theta\) = 2
tan2 \(\theta\) = 1
but \(\theta\) = 45o
tan2 45o = 12
= 1
\(\theta\) = 45o

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