In the parallelogram PQRS, PE is perpendicular to QR. Find the area of the parallelogram.
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Correct Answer: Option D
Explanation:
By Pythagoras, PE2 = 132 - 52
= 169 - 144 = 144
h = PE = 144 = 12cm,
Area of 11gm = b x h
QR = b =(5 + 7)cm = 12cm
area = 12 x 12
= 144cm2
By Pythagoras, PE2 = 132 - 52
= 169 - 144 = 144
h = PE = 144 = 12cm,
Area of 11gm = b x h
QR = b =(5 + 7)cm = 12cm
area = 12 x 12
= 144cm2