A pentagon has four of its angles equal. If the size of the fifth angle is 60o, Find the size of each of the four equal angles.
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Correct Answer: Option C
Explanation:
The sum of interior angle of pentagon
(5 sides) = (2n - 4) x 90o
n = 5
(2 x 5 - 4) x 90o = 6 x 90o
= 540o
540o - 60o = 480o \(\div\) 4
= 120o
The sum of interior angle of pentagon
(5 sides) = (2n - 4) x 90o
n = 5
(2 x 5 - 4) x 90o = 6 x 90o
= 540o
540o - 60o = 480o \(\div\) 4
= 120o