(\(\frac{x^a}{x^b}\))a + b by (\(\frac{x^{a + b}}{x^{a - b}}\))\(\frac{a^2}{b}\)
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Correct Answer: Option D
Explanation:
(\(\frac{x^a}{x^b}\))a + b = (\(\frac{x^{a2 + ab}}{x^{b2 + ab}}\))
= xa2 - b2
{\(\frac{xa + b}{xa - b}\)} = xa + b - a + b
= x2b
= x2a
= xa2 - b2
= xb2 \(\div \) a2 = \(\frac{1}{x^\text a2 + b2}\)
(\(\frac{x^a}{x^b}\))a + b = (\(\frac{x^{a2 + ab}}{x^{b2 + ab}}\))
= xa2 - b2
{\(\frac{xa + b}{xa - b}\)} = xa + b - a + b
= x2b
= x2a
= xa2 - b2
= xb2 \(\div \) a2 = \(\frac{1}{x^\text a2 + b2}\)