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Wednesday, 04 March 2026
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In the figure, PS = SR and Rx is a tangent to the circle at R, < QRX is equal to ...



In the figure, PS = SR and Rx is a tangent to the circle at R, < QRX is equal to 72o. Find
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  • A 20o
  • B 36o
  • C 72o
  • D 30o
  • E 15o
Correct Answer: Option B
Explanation:

XRQ = RSQ (Alternate segment)

s = 72o

(80o - 72o = 180o)

a + b + c = 190o = 2b + c = 180o

2b + 108 = 180o

2b = 72o

b = 36o

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