In \(\bigtriangleup\)XYZ, XY = 3cm, XZ = 5cm and YZ = 7cm. If the bisector of XYZ meets XZ at W, what is the length of XW?
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Correct Answer: Option A
Explanation:
Let XW = a, a :7
\(\frac{a}{5 - a}\) = \(\frac{3}{7}\)
7a = 15 - 3a
10a = 15
a = \(\frac{15}{10}\)
= \(\frac{3}{2}\)
= 1.5cm
Let XW = a, a :7
\(\frac{a}{5 - a}\) = \(\frac{3}{7}\)
7a = 15 - 3a
10a = 15
a = \(\frac{15}{10}\)
= \(\frac{3}{2}\)
= 1.5cm