What is the size of an exterior angle of a regular pentagon?
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Correct Answer: Option C
Explanation:
Pentagon is a polygon with 5 sides. Sum of interior angles of polygon (regular) = (2n - 4) x 90o
= 5
= (10 - 4) x 90o
= 540o
each interior angle = \(\frac{540}{5}\)
= 108o
= 180o let x represent ext. angle
x + 108o = 180v
x = 180o - 108o
= 72o
Pentagon is a polygon with 5 sides. Sum of interior angles of polygon (regular) = (2n - 4) x 90o
= 5
= (10 - 4) x 90o
= 540o
each interior angle = \(\frac{540}{5}\)
= 108o
= 180o let x represent ext. angle
x + 108o = 180v
x = 180o - 108o
= 72o