A stone Q is tied to a point P vertically above Q by an inelastic string of length 2 meters. How high does the stone rise when the string is inclined at an angle 60o to the vertical?
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Correct Answer: Option D
Explanation:
Cos 60o = \(\frac{PD}{2}\)
Cos 60o x 2 = 0.5 x 2
= 1m
Cos 60o = \(\frac{PD}{2}\)
Cos 60o x 2 = 0.5 x 2
= 1m