A trader realises 10x - x\(^2\) Naira profit from the sale of x bags of corn. How many bags will give him the maximum profit?
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Correct Answer: Option C
Explanation:
Profit (P) = 10\(_x\) − \(_x\)2
Maximum profit can be achieved when the differential of profit with respect to number of bags(x) is 0
i.e. \(\frac{dp}{dx}\) = 0
\(\frac{dp}{dx}\) = 10 - 2x = 0
10 = 2x
Then x = \(\frac{10}{2}\) = 5
Profit (P) = 10\(_x\) − \(_x\)2
Maximum profit can be achieved when the differential of profit with respect to number of bags(x) is 0
i.e. \(\frac{dp}{dx}\) = 0
\(\frac{dp}{dx}\) = 10 - 2x = 0
10 = 2x
Then x = \(\frac{10}{2}\) = 5