Determine the mean monthly salary of 50 employees of a company from the following frequency distribution.
\(\begin{array}{c|c} \text{Monthly salary} & \text{Frequency}\\\hline N200.00 & 10\\ N325.00 & 5\\N100.00 & 20\\N120.00 & 2\\ N60.00 & 10\\ N80.00 & 3\end{array}\)
\(\begin{array}{c|c} \text{Monthly salary} & \text{Frequency}\\\hline N200.00 & 10\\ N325.00 & 5\\N100.00 & 20\\N120.00 & 2\\ N60.00 & 10\\ N80.00 & 3\end{array}\)
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Correct Answer: Option B
Explanation:
\(\bar{x}\) = \(\frac{fx}{N}\)
= \(\frac{6705}{50}\)
= 1341
= N134.10
\(\bar{x}\) = \(\frac{fx}{N}\)
= \(\frac{6705}{50}\)
= 1341
= N134.10