If 0.0000152 x 0.042 = A x 108, where 1 \(\leq\) A < 10, find A and B
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Correct Answer: Option B
Explanation:
0.0000152 x 0.042 = A x 108
1 \(\leq\) A < 10, it means values of A includes 1 - 9
0.0000152 = 1.52 x 10-5
0.00042 = 4.2 x 10-4
1.52 x 4.2 = 6.384
10-5 x 10-4
= 10-5-4
= 10-9
= 6.38 x 10-9
A = 6.38, B = -9
0.0000152 x 0.042 = A x 108
1 \(\leq\) A < 10, it means values of A includes 1 - 9
0.0000152 = 1.52 x 10-5
0.00042 = 4.2 x 10-4
1.52 x 4.2 = 6.384
10-5 x 10-4
= 10-5-4
= 10-9
= 6.38 x 10-9
A = 6.38, B = -9