If sin \(\theta\) = \(\frac{x}{y}\) and 0o < 90o then find \(\frac{1}{tan\theta}\)
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Correct Answer: Option D
Explanation:
\(\frac{1}{tan\theta}\) = \(\frac{cos\theta}{sin\theta}\)
sin\(\theta\) = \(\frac{x}{y}\)
cos\(\theta\) = \(\frac{\sqrt{y^2 - x^2}}{y}\)
\(\frac{1}{tan\theta}\) = \(\frac{cos\theta}{sin\theta}\)
sin\(\theta\) = \(\frac{x}{y}\)
cos\(\theta\) = \(\frac{\sqrt{y^2 - x^2}}{y}\)