In the figure, Ois the centre of circle PQRS and PS//RT. If PRT = 135, then PSO is

In the figure, O is the centre of circle PQRS and PS//RT. If PRT = 135, then PSO is

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A 67\(\frac{1}{2}\)^o
B 22\(\frac{1}{2}\)^o
C 33\(\frac{1}{2}\)^o
D 45^o
E 90^o

Correct Answer: Option D

Explanation:
< R = 180^o - 45^o (sum of angles on a straight line)

< R = < P = 45^o (corresponding angles)

< PSO = < P = 45^o (\(\bigtriangleup\)PSO is a right angle)

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In the figure, Ois the centre of circle PQRS and PS//RT. If PRT = 135, then PSO is

Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE

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