Explanation:
3^2y + 6(3^y) = 27
This can be rewritten as (3^y)² + 6(3^y) = 27
Let 3^y = x
x² + 6x - 27 = 0
(x + 9)(x - 3) = 0
when x - 3 = 0, x = 3
sub. for x in 3y = x
3^y = 3
log₃3 = y
y = 1