Two points X and Y both on latitude 60oS have longitude147oE and 153oW respectively. Find to the nearest kilometer the distance between X and Y measured along the parallel of latitude(Take 2\(\pi\)R = 4 x 104km, where R is the radius of the earth)
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Correct Answer: Option A
Explanation:
Length of an area = \(\frac{\theta}{360}\) x 2\(\pi\)r
Longitude difference = 147 + 153 = 30NoN
distance between xy = \(\frac{\theta}{360}\) x 2\(\pi\)R cos60o
= \(\frac{300}{360}\) x 4 x 104 x \(\frac{1}{2}\)
= 1.667 x 104km(1667 km)
Length of an area = \(\frac{\theta}{360}\) x 2\(\pi\)r
Longitude difference = 147 + 153 = 30NoN
distance between xy = \(\frac{\theta}{360}\) x 2\(\pi\)R cos60o
= \(\frac{300}{360}\) x 4 x 104 x \(\frac{1}{2}\)
= 1.667 x 104km(1667 km)