In the figure, PQ is the tangent from P to the circle QRS with SR as its diameter. If QRS = \(\theta\)oand RQP = \(\phi\)o, which of the following relationships between \(\theta\)o and \(\phi\)o is correct

In the figure, PQ is the tangent from P to the circle QRS with SR as its diameter. If QRS = \(\theta\)^oand RQP = \(\phi\)^o, which of the following relationships between \(\theta\)^o and \(\phi\)^o is correct

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A \(\theta\)^o + \(\phi\)^o = 90²
B \(\phi\)^o = 90² - 2\(\theta\)^o
C \(\theta\)^o = \(\phi\)^o
D \(\phi\)^o = 2\(\theta\)^o
E \(\theta\)^o + 2\(\phi\)^o

Correct Answer: Option E

Explanation:
180 - \(\phi\)^o = \(\theta\)^o + \(\phi\)^o (Sum of opposite interior angle equal to its exterior angle)

180 = 2\(\phi\) + \(\theta\)^o

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In the figure, PQ is the tangent from P to the circle QRS with SR as its diameter. If ...

Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE

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