If y = \(\frac{x}{x - 3}\) + \(\frac{x}{x + 4}\) find y when x = -2
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option A
Explanation:
y = \(\frac{x}{x - 3}\) + \(\frac{x}{x + 4}\) when x = -2
y = \(\frac{-2}{-5}\) + \(\frac{(-2)}{-2 + 4}\)
= \(\frac{2}{5}\) + \(\frac{-2}{2}\)
= \(\frac{4 -10}{10}\)
= \(\frac{-6}{10}\)
= -\(\frac{3}{5}\)
y = \(\frac{x}{x - 3}\) + \(\frac{x}{x + 4}\) when x = -2
y = \(\frac{-2}{-5}\) + \(\frac{(-2)}{-2 + 4}\)
= \(\frac{2}{5}\) + \(\frac{-2}{2}\)
= \(\frac{4 -10}{10}\)
= \(\frac{-6}{10}\)
= -\(\frac{3}{5}\)