In the diagram, PQ and RS are chords of a circle centre O which meet at T outside the circle. If TP = 24cm. TQ = 8cm and TS = 12cm, find TR.
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Correct Answer: Option A
Explanation:
PT x QT = TR x TS
24 x 8 = TR x 12
TR = \(\frac{24 \times 8}{12}\)
= 16cm
PT x QT = TR x TS
24 x 8 = TR x 12
TR = \(\frac{24 \times 8}{12}\)
= 16cm