Find \(\int (x^{2} + 3x-5)dx\)
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option C
Explanation:
∫xndx = \(\frac{x_{n + 1}}{n + 1}\)
∫dx = x + k
where k is constant
∫(x2 + 3x − 5)dx
∫x2 dx + ∫3xdx − ∫5dx
\(\frac{2_{2 + 1}}{2 + 1}\) + \(\frac{3x^{1 + 1}}{1 + 1}\) − 5x + k
\(\frac{x_3}{3}\) + \(\frac{3x_2}{2}\) − 5x + k
∫xndx = \(\frac{x_{n + 1}}{n + 1}\)
∫dx = x + k
where k is constant
∫(x2 + 3x − 5)dx
∫x2 dx + ∫3xdx − ∫5dx
\(\frac{2_{2 + 1}}{2 + 1}\) + \(\frac{3x^{1 + 1}}{1 + 1}\) − 5x + k
\(\frac{x_3}{3}\) + \(\frac{3x_2}{2}\) − 5x + k