The trapezium PQRS parallel to SR,∠PQS = 34o and ∠SPQ = 2 ∠SRQ. Find the size of, SQR
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Correct Answer: Option D
Explanation:
considering SPQ
S = 34o (base ∠s of Isos. Δ)
P = 180o - 68o = 112o
R = 122/2 = 56o
a = 34o (alt ∠s)
SQR = 180o - (56 + 34)
180o - 90o = 90o
considering SPQ
S = 34o (base ∠s of Isos. Δ)
P = 180o - 68o = 112o
R = 122/2 = 56o
a = 34o (alt ∠s)
SQR = 180o - (56 + 34)
180o - 90o = 90o