A bag contains 3 red, 4 black and 5 green identical balls. Two balls are picked at random, one after the other without replacement. Find the probability that one is red and the other is green
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Correct Answer: Option C
Explanation:
Total balls = 12
RG or GR
3/12
x
5/11
+
5/12
x
3/11
5/44
+
5/44
=
10/44
=
5/22
Total balls = 12
RG or GR
3/12
x
5/11
+
5/12
x
3/11
5/44
+
5/44
=
10/44
=
5/22