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For what values of x is the curve y = \(\frac{x^2 + 3}{x + 4}\) decreasing?
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Mathematics Classroom
Jamb
Jamb 1988
ALGEBRA
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For what values of x is the curve y = \(\frac{x^2 + 3}{x + 4}\) decreasing?
SchoolNGR Classroom
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
A
-3 < x \(\leq\) 0
B
-3 \(\geq\) x < 0
C
0 < x < 3
D
0 \(\leq\) x \(\leq\) 3
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Correct Answer:
Option D
Explanation:
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