Solve the following equation equation for \(x^2 + \frac{2x}{r^2} + \frac{1}{r^4}\) = 0
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Correct Answer: Option C
Explanation:
\(x^2 + \frac{2x}{r^2}\) + \(\frac{1}{r^4}\) = 0
(x + \(\frac{1}{r^2}\)) = 0
x + \(\frac{1}{r^2}\) = 0
x = \(\frac{-1}{r^2}\)
\(x^2 + \frac{2x}{r^2}\) + \(\frac{1}{r^4}\) = 0
(x + \(\frac{1}{r^2}\)) = 0
x + \(\frac{1}{r^2}\) = 0
x = \(\frac{-1}{r^2}\)