Make R the subject of the fomula S = \(\sqrt{\frac{2R + T}{2RT}}\)
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option B
Explanation:
S = \(\sqrt{\frac{2R + T}{2RT}}\)
Squaring both sides,Â
\(S^{2} = \frac{2R + T}{2RT}\)
\(S^{2} (2RT) = 2R + T\)
\(2S^{2} RT - 2R = T\)
\(R = \frac{T}{2TS^{2} Â - 2}\)
= \(\frac{T}{2(TS^{2}Â - 1)}
S = \(\sqrt{\frac{2R + T}{2RT}}\)
Squaring both sides,Â
\(S^{2} = \frac{2R + T}{2RT}\)
\(S^{2} (2RT) = 2R + T\)
\(2S^{2} RT - 2R = T\)
\(R = \frac{T}{2TS^{2} Â - 2}\)
= \(\frac{T}{2(TS^{2}Â - 1)}