Solve for a positive number x such that \(2^{(x^3 - x^2 - 2x)} = 1\)
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Correct Answer: Option C
Explanation:
\(2^{(x^3 - x^2 - 2x)} = 1\)
\(x^3 - x^2 - 2x = 0\)
\(x(x^2 - x - 2) = 0\)
\(x^2 - x - 2 = 0\)
\((x + 1)(x - 2) = 0\)
x = 2 is the positive answer.
\(2^{(x^3 - x^2 - 2x)} = 1\)
\(x^3 - x^2 - 2x = 0\)
\(x(x^2 - x - 2) = 0\)
\(x^2 - x - 2 = 0\)
\((x + 1)(x - 2) = 0\)
x = 2 is the positive answer.