4sin2 x - 3 = 0, find x if 0 \(\geq\) x \(\geq\) 90o
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option C
Explanation:
4 sin2x - 3 = 0
sin2x = \(\frac{3}{4}\)
Sin x = \(\pm\) \(\sqrt{\frac{3}{4}}\)
= \(\pm\) \(\sqrt{\frac{3}{4}}\)
= 60o
4 sin2x - 3 = 0
sin2x = \(\frac{3}{4}\)
Sin x = \(\pm\) \(\sqrt{\frac{3}{4}}\)
= \(\pm\) \(\sqrt{\frac{3}{4}}\)
= 60o