Simplify \(\sqrt{160r^2 + \sqrt{71r^4 + \sqrt{100r^8}}}\)
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Correct Answer: Option C
Explanation:
\(\sqrt{160r^2Â + \sqrt{71r^4Â + \sqrt{100r^8}}}\)
Simplifying from the innermost radical and progressing outwards we have the given expression
\(\sqrt{160r^2 + \sqrt{71r^4 + \sqrt{100r^8}}}\) = \(\sqrt{160r^2 + \sqrt{71r^4 + 10r^4}}\)
= \(\sqrt{160r^2 + \sqrt{81r^4}}\)
\(\sqrt{160r^2 + 9r^2}\) = \(\sqrt{169r^2}\)
= 13r
\(\sqrt{160r^2Â + \sqrt{71r^4Â + \sqrt{100r^8}}}\)
Simplifying from the innermost radical and progressing outwards we have the given expression
\(\sqrt{160r^2 + \sqrt{71r^4 + \sqrt{100r^8}}}\) = \(\sqrt{160r^2 + \sqrt{71r^4 + 10r^4}}\)
= \(\sqrt{160r^2 + \sqrt{81r^4}}\)
\(\sqrt{160r^2 + 9r^2}\) = \(\sqrt{169r^2}\)
= 13r