If a = 2, b = -2 and c = -\(\frac{1}{2}\), evaluate (ab2 - bc2)(a2c - abc)
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option D
Explanation:
(ab2 - bc2)(a2c - abc)
[2(2)2 - (- 2x\(\frac{1}{2}\))] [22(-\(\frac{1}{2}\)) - 2(-2)(-\(\frac{1}{2}\))]
[8 = \(\frac{1}{2}\)][-2 - 2] = \(\frac{17}{2}\) x 42
= -34
(ab2 - bc2)(a2c - abc)
[2(2)2 - (- 2x\(\frac{1}{2}\))] [22(-\(\frac{1}{2}\)) - 2(-2)(-\(\frac{1}{2}\))]
[8 = \(\frac{1}{2}\)][-2 - 2] = \(\frac{17}{2}\) x 42
= -34