A dealer increased the price of an item by 20%, then increased the price of the same item by 30%. If x is the original price what is the price after the two increment?
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Correct Answer: Option B
Explanation:
To find the final price of an item after two successive price increases, we can follow these steps:
1. First Increase:
- The original price is \( x \).
- The price is increased by 20%.
- New price after the first increase:
\[
\text{New Price} = x + 0.20x = 1.20x
\]
2. Second Increase:
- This new price is then increased by 30%.
- New price after the second increase:
\[
\text{New Price} = 1.20x + 0.30 \times 1.20x = 1.20x \times (1 + 0.30) = 1.20x \times 1.30
\]
- Calculate:
\[
1.20 \times 1.30 = 1.56
\]
Thus, the final price after the two increments is \( 1.56x \).
The correct answer is B. 1.56x.
To find the final price of an item after two successive price increases, we can follow these steps:
1. First Increase:
- The original price is \( x \).
- The price is increased by 20%.
- New price after the first increase:
\[
\text{New Price} = x + 0.20x = 1.20x
\]
2. Second Increase:
- This new price is then increased by 30%.
- New price after the second increase:
\[
\text{New Price} = 1.20x + 0.30 \times 1.20x = 1.20x \times (1 + 0.30) = 1.20x \times 1.30
\]
- Calculate:
\[
1.20 \times 1.30 = 1.56
\]
Thus, the final price after the two increments is \( 1.56x \).
The correct answer is B. 1.56x.