A reduction of 25% in the price of an article enables a man to buy 50 kilograms more for N500. What is the reduced price per kilogram?
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Correct Answer: Option C
Explanation:
To find the reduced price per kilogram of the article, follow these steps:
1. Determine the original price per kilogram:
Let \( P \) be the original price per kilogram in Naira.
The reduction of 25% means the new price is 75% of the original price. So, the reduced price per kilogram is:
\[
0.75P
\]
2. Calculate how much more of the article can be bought with the reduced price:
With the original price, the amount of article that can be bought for N500 is:
\[
\frac{500}{P} \text{ kilograms}
\]
With the reduced price, the amount of article that can be bought for N500 is:
\[
\frac{500}{0.75P} \text{ kilograms}
\]
3. Find the difference in the amount of article bought:
The difference in the amount of article that can be bought is:
\[
\frac{500}{0.75P} - \frac{500}{P}
\]
Simplify this expression:
\[
\frac{500}{0.75P} = \frac{500 \times 4}{3P} = \frac{2000}{3P}
\]
\[
\frac{500}{P} = \frac{500}{P}
\]
\[
\frac{2000}{3P} - \frac{500}{P} = \frac{2000 - 1500}{3P} = \frac{500}{3P}
\]
This difference is given as 50 kilograms:
\[
\frac{500}{3P} = 50
\]
4. Solve for \( P \):
Rearranging the equation to find \( P \):
\[
500 = 150P
\]
\[
P = \frac{500}{150} = \frac{10}{3} \approx 3.33
\]
So, the reduced price per kilogram, which is 75% of the original price, is:
\[
0.75 \times \frac{10}{3} = \frac{7.5}{3} = 2.50
\]
The reduced price per kilogram is N2.50.
The correct answer is C. N2.50.
To find the reduced price per kilogram of the article, follow these steps:
1. Determine the original price per kilogram:
Let \( P \) be the original price per kilogram in Naira.
The reduction of 25% means the new price is 75% of the original price. So, the reduced price per kilogram is:
\[
0.75P
\]
2. Calculate how much more of the article can be bought with the reduced price:
With the original price, the amount of article that can be bought for N500 is:
\[
\frac{500}{P} \text{ kilograms}
\]
With the reduced price, the amount of article that can be bought for N500 is:
\[
\frac{500}{0.75P} \text{ kilograms}
\]
3. Find the difference in the amount of article bought:
The difference in the amount of article that can be bought is:
\[
\frac{500}{0.75P} - \frac{500}{P}
\]
Simplify this expression:
\[
\frac{500}{0.75P} = \frac{500 \times 4}{3P} = \frac{2000}{3P}
\]
\[
\frac{500}{P} = \frac{500}{P}
\]
\[
\frac{2000}{3P} - \frac{500}{P} = \frac{2000 - 1500}{3P} = \frac{500}{3P}
\]
This difference is given as 50 kilograms:
\[
\frac{500}{3P} = 50
\]
4. Solve for \( P \):
Rearranging the equation to find \( P \):
\[
500 = 150P
\]
\[
P = \frac{500}{150} = \frac{10}{3} \approx 3.33
\]
So, the reduced price per kilogram, which is 75% of the original price, is:
\[
0.75 \times \frac{10}{3} = \frac{7.5}{3} = 2.50
\]
The reduced price per kilogram is N2.50.
The correct answer is C. N2.50.