What is the sum of the sequence: 10, 20, 30,..., 1000?
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Correct Answer: Option C
Explanation:
To find the sum of the arithmetic sequence \(10, 20, 30, \ldots, 1000\), follow these steps:
1. Identify the first term (\(a\)) and the common difference (\(d\)):
- First term \(a = 10\)
- Common difference \(d = 20 - 10 = 10\)
2. Find the number of terms (\(n\)):
The general term of the arithmetic sequence is given by:
\[
a_n = a + (n - 1)d
\]
Set \(a_n = 1000\):
\[
1000 = 10 + (n - 1) \times 10
\]
\[
1000 = 10 + 10(n - 1)
\]
\[
1000 = 10 + 10n - 10
\]
\[
1000 = 10n
\]
\[
n = \frac{1000}{10} = 100
\]
So, there are 100 terms in the sequence.
3. Calculate the sum of the sequence:
The sum \(S_n\) of the first \(n\) terms of an arithmetic sequence is given by:
\[
S_n = \frac{n}{2} \times (a + l)
\]
where \(l\) is the last term. Here, \(l = 1000\), \(a = 10\), and \(n = 100\):
\[
S_{100} = \frac{100}{2} \times (10 + 1000)
\]
\[
S_{100} = 50 \times 1010
\]
\[
S_{100} = 50,500
\]
Thus, the sum of the sequence is:
C. 50,500
To find the sum of the arithmetic sequence \(10, 20, 30, \ldots, 1000\), follow these steps:
1. Identify the first term (\(a\)) and the common difference (\(d\)):
- First term \(a = 10\)
- Common difference \(d = 20 - 10 = 10\)
2. Find the number of terms (\(n\)):
The general term of the arithmetic sequence is given by:
\[
a_n = a + (n - 1)d
\]
Set \(a_n = 1000\):
\[
1000 = 10 + (n - 1) \times 10
\]
\[
1000 = 10 + 10(n - 1)
\]
\[
1000 = 10 + 10n - 10
\]
\[
1000 = 10n
\]
\[
n = \frac{1000}{10} = 100
\]
So, there are 100 terms in the sequence.
3. Calculate the sum of the sequence:
The sum \(S_n\) of the first \(n\) terms of an arithmetic sequence is given by:
\[
S_n = \frac{n}{2} \times (a + l)
\]
where \(l\) is the last term. Here, \(l = 1000\), \(a = 10\), and \(n = 100\):
\[
S_{100} = \frac{100}{2} \times (10 + 1000)
\]
\[
S_{100} = 50 \times 1010
\]
\[
S_{100} = 50,500
\]
Thus, the sum of the sequence is:
C. 50,500