Explanation:
To find the 11th term of the sequence \(1, 3, 9, 27, \ldots\), we note that it is a geometric sequence where:

- The first term \(a = 1\)
- The common ratio \(r = 3\)

The general term of a geometric sequence is given by:

\[ a_n = a \cdot r^{(n - 1)} \]

For the 11th term (\(n = 11\)):

\[ a_{11} = 1 \cdot 3^{(11 - 1)} \]

\[ a_{11} = 3^{10} \]

So, the 11th term of the sequence is \(3^{10}\).

Thus, the correct answer is:

D. \(3^{10}\)