n!/(n-3)! = ?
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Correct Answer: Option C
Explanation:
The expression \(\frac{n!}{(n-3)!}\) can be simplified as follows:
\[
\frac{n!}{(n-3)!} = \frac{n \times (n-1) \times (n-2) \times (n-3)!}{(n-3)!}
\]
The \((n-3)!\) terms cancel out, leaving:
\[
n \times (n-1) \times (n-2)
\]
So, the correct answer is:
C. \( n(n-1)(n-2) \).
The expression \(\frac{n!}{(n-3)!}\) can be simplified as follows:
\[
\frac{n!}{(n-3)!} = \frac{n \times (n-1) \times (n-2) \times (n-3)!}{(n-3)!}
\]
The \((n-3)!\) terms cancel out, leaving:
\[
n \times (n-1) \times (n-2)
\]
So, the correct answer is:
C. \( n(n-1)(n-2) \).