Find the range of values of x which satisfy the inequality \(\frac{x}{2}\) + \(\frac{x}{3}\) + \(\frac{x}{4}\) < 1
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Correct Answer: Option A
Explanation:
\(\frac{x}{2}\) + \(\frac{x}{3}\) + \(\frac{x}{4}\) < 1
= \(\frac{6x + 4x + 3x < 12}{12}\)
i.e. 13 x < 12 = x < \(\frac{12}{13}\)
\(\frac{x}{2}\) + \(\frac{x}{3}\) + \(\frac{x}{4}\) < 1
= \(\frac{6x + 4x + 3x < 12}{12}\)
i.e. 13 x < 12 = x < \(\frac{12}{13}\)