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Wednesday, 10 June 2026
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For all 0, sin0 + sin(-0) + cos0 + cos(-0) + tan0 + tan(-0) =?

For all 0, sin0 + sin(-0) + cos0 + cos(-0) + tan0 + tan(-0) =?
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  • A 2Sin0
  • B 2cos0
  • C 2tan0
  • D 2sin0 tan0
Correct Answer: Option B
Explanation:
Let's break down the expression:

For \( \theta = 0 \):

- \( \sin(0) = 0 \)
- \( \sin(-0) = \sin(0) = 0 \) (since sine is an odd function)
- \( \cos(0) = 1 \)
- \( \cos(-0) = \cos(0) = 1 \) (since cosine is an even function)
- \( \tan(0) = 0 \)
- \( \tan(-0) = \tan(0) = 0 \) (since tangent is an odd function)

Substitute these values into the expression:

\[
\sin(0) + \sin(-0) + \cos(0) + \cos(-0) + \tan(0) + \tan(-0)
\]

\[
= 0 + 0 + 1 + 1 + 0 + 0
\]

\[
= 2
\]

So the expression simplifies to \(2 \cos(0)\), where \(\cos(0) = 1\).

Thus, the correct answer is:

B. 2 cos(0)

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