If cos x = \(\sqrt{\frac{a}{b}}\) find cosec x
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Correct Answer: Option C
Explanation:
cosx = \(\sqrt{\frac{a}{b}}\)
y2 + \(\sqrt{(a)^2}\) = \(\sqrt{(b)^2}\) by pythagoras
y2 = b - a
∴ y = b - a
cosec x = \(\frac{1}{sin x}\) = \(\frac{1}{y}\)
\(\frac{b}{y}\) = \(\frac{\sqrt{b}}{\sqrt{b - a}}\)
= \(\sqrt{\frac{b}{b - a}}\)
cosx = \(\sqrt{\frac{a}{b}}\)
y2 + \(\sqrt{(a)^2}\) = \(\sqrt{(b)^2}\) by pythagoras
y2 = b - a
∴ y = b - a
cosec x = \(\frac{1}{sin x}\) = \(\frac{1}{y}\)
\(\frac{b}{y}\) = \(\frac{\sqrt{b}}{\sqrt{b - a}}\)
= \(\sqrt{\frac{b}{b - a}}\)