In this figure, PQ = PR = PS and SRT = 68o. Find QPS

In this figure, PQ = PR = PS and SRT = 68^o. Find QPS

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A 136^o
B 124^o
C 12^o
D 68^o

Correct Answer: Option A

Explanation:

Since PQRS is quadrilateral 2y + 2x = QPS = 360^o
i.e. 2(y + x) + QPS = 360^o
QPS = 360^o - 2(y + x)
But x + y + 68^o = 180^o
x + y = 180^o - 68^o = 180^o
x + y = 180^o - 68^o
= 112^o
QPS = 360^o - 2(112^o)
360^o - 224^o = 136^o

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In this figure, PQ = PR = PS and SRT = 68o. Find QPS

Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE

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