Make t the subject of formula S = ut + \(\frac{1}{2} at^2\)
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Correct Answer: Option A
Explanation:
Given S = ut + \(\frac{1}{2} at^2\)
S = ut + \(\frac{1}{2} at^2\)
∴ 2S = 2ut + at2
= at2 + 2ut - 2s = 0
t = \(\frac{-2u \pm 4u^2 + 2as}{2a}\)
= -2u \(\pi\) \(\frac{\sqrt{u^2 4u^2 + 2as}}{2a}\)
= \(\frac{1}{a}\) (-u + \(\sqrt{U^2 - 2as}\))
Given S = ut + \(\frac{1}{2} at^2\)
S = ut + \(\frac{1}{2} at^2\)
∴ 2S = 2ut + at2
= at2 + 2ut - 2s = 0
t = \(\frac{-2u \pm 4u^2 + 2as}{2a}\)
= -2u \(\pi\) \(\frac{\sqrt{u^2 4u^2 + 2as}}{2a}\)
= \(\frac{1}{a}\) (-u + \(\sqrt{U^2 - 2as}\))