If the binary operation \(\ast\) is defined by m \(\ast\) n = mn + m + n for any real number m and n, find the identity of the elements under this operation
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Correct Answer: Option B
Explanation:
m \(\ast\) n = mn + m + n
m \(\ast\) e = me + m + e, e \(\ast\) m = e
∴ me + m + e, m(e + 1)e - e = 0
e + 1 = 0
∴ e = -1
m \(\ast\) n = mn + m + n
m \(\ast\) e = me + m + e, e \(\ast\) m = e
∴ me + m + e, m(e + 1)e - e = 0
e + 1 = 0
∴ e = -1