The diagram is a circle with centre O. Find the area of the shaded portion
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Correct Answer: Option A
Explanation:
Area of the quadrant = \(\frac{1}{4} \pi r^2 = \frac{1}{4} \pi (6)^2\)
= \(\frac{36 \pi}{4} = 9 \pi \)
Area of the triangle = \(\frac{1}{2} \times 6 = 18 \times \sin 90^o = 18\)
Area of shaded portion =(9 \(\pi \) - 18)cm^2\) =
9(\(\pi - 2)cm^2\).
Area of the quadrant = \(\frac{1}{4} \pi r^2 = \frac{1}{4} \pi (6)^2\)
= \(\frac{36 \pi}{4} = 9 \pi \)
Area of the triangle = \(\frac{1}{2} \times 6 = 18 \times \sin 90^o = 18\)
Area of shaded portion =(9 \(\pi \) - 18)cm^2\) =
9(\(\pi - 2)cm^2\).