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\(\begin{array}{c|c} \oplus mod 10 2 4 6 8 \\ \hline 2 4 8 2 6 \\4 8 6 4 ...

\(\begin{array}{c|c} \oplus mod 10 & 2 & 4 & 6 & 8 \\ \hline 2 & 4 & 8 & 2 & 6 \\4 & 8 & 6 & 4 & 2\\ 4 & 8 & 6 & 4 & 2\\ 6 & 2 & 4 & 6 & 8\\ 8 & 6 & 2 & 8 & 4\end{array}\)
The multiplication table above has modulo 10 on the set S = (2, 4, 6, 8). Find the inverse of 2
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  • A 2
  • B 4
  • C 6
  • D 8
Correct Answer: Option A
Explanation:
The inverse of 2 is 6 since 2 x 6 = 12; under mod 10
12 = 2 which is also the value required

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