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\(\begin{array}{c|c} \text{Class Interval} 1 - 5 6 - 10 11 - 15 16 - 20 21 - 25 \\ ...

\(\begin{array}{c|c} \text{Class Interval} & 1 - 5 & 6 - 10 & 11 - 15 & 16 - 20 & 21 - 25 \\ \hline Frequency & 6 & 15 & 20 & 7 & 2\end{array}\)
Estimate the median of the frequency distribution above
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  • A 10\(\frac{1}{2}\)
  • B 11\(\frac{1}{2}\)
  • C 12
  • D 13
Correct Answer: Option C
Explanation:
Median = L + [\(\frac{\frac{N}{2} - f}{fm}\)]h
N = Sum of frequencies
L = lower class boundary of median class
f = sum of all frequencies below L
fm = frequency of modal class and
h = class width of median class
Median = 11 + [\(\frac{\frac{50}{2} - 21}{20}\)]5
= 11 + (\(\frac{25 - 21}{20}\))5
= 11 + (\(\frac{(4)}{20}\))
11 + 1 = 12

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