In the diagram, O is the centre of the circle. If SOQ is a diameter and lt; PRS is 38o, what is the value of lt; PSQ

In the diagram, O is the centre of the circle. If SOQ is a diameter and < PRS is 38^o, what is the value of < PSQ

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A 148^o
B 104^o
C 80^o
D 52^o

Correct Answer: Option D

Explanation:
< SRP = < SQP = 38^o (angle in the same segment of a circle are equal)
But < SPQ = 90^o (angle in a semicircle)
also < PSQ + < SQP + < SPQ = 180^o (angles in a triangle = 180^o)
< PSQ + 38^o + 90^o = 190^o
< PSQ = 128^o = 180^o
PSQ = 180^o - 128^o
PSQ = 52^o

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In the diagram, O is the centre of the circle. If SOQ is a diameter and lt; PRS is ...

Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE

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