Factorize completely the expression \(abx^2 + 6y - 3ax - 2byx\)
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option A
Explanation:
\(abx^{2} + 6y - 3ax - 2byx\)
Collecting like terms, we have
\(abx^{2} - 3ax + 6y - 2byx\)
= \(ax(bx - 3) + 2y(3 - bx)\)
= \(ax(bx - 3) - 2y(bx - 3)\)
= \((ax - 2y)(bx - 3)\)
\(abx^{2} + 6y - 3ax - 2byx\)
Collecting like terms, we have
\(abx^{2} - 3ax + 6y - 2byx\)
= \(ax(bx - 3) + 2y(3 - bx)\)
= \(ax(bx - 3) - 2y(bx - 3)\)
= \((ax - 2y)(bx - 3)\)