A room is 12m long, 9m wide and 8m high. Find the cosine of the angle which a diagonal of the room makes with the floor of the room
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Correct Answer: Option A
Explanation:
ABCD is the floor. By pathagoras \(^2\) = 144 + 81 = \(\sqrt{225}\) = 15cm
Height of room 8m, diagonal of floor is 15m
Therefore, the cosine of the angle which a diagonal of the room makes with the floor is
\(^2\) = 15\(^2\) + 8\(^2\) cosine
\(\frac{adj}{Hyp} = \frac{15}{17}\)
\(^2\) = \(\sqrt{225 + 64}\)
= \(\sqrt{289}\)
= 17
ABCD is the floor. By pathagoras \(^2\) = 144 + 81 = \(\sqrt{225}\) = 15cm
Height of room 8m, diagonal of floor is 15m
Therefore, the cosine of the angle which a diagonal of the room makes with the floor is
\(^2\) = 15\(^2\) + 8\(^2\) cosine
\(\frac{adj}{Hyp} = \frac{15}{17}\)
\(^2\) = \(\sqrt{225 + 64}\)
= \(\sqrt{289}\)
= 17