The sum of the interior angle of pentagon is 6x + 6y. Find y in terms of x.
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Correct Answer: Option B
Explanation:
Sum of interior angles = (2n - 4) 90\(^o\)
or perntagon, n = 5
Sum of interior angles = 6 x 90\(^o\) = 540\(^o\)
6x + 6y = 540\(^o\)
6(x + y) = 540\(^o\)
x + y = \(\frac{540^o}{6}\) = 90\(^o\)
y = 90\(^o\)
y = 90 - x
Sum of interior angles = (2n - 4) 90\(^o\)
or perntagon, n = 5
Sum of interior angles = 6 x 90\(^o\) = 540\(^o\)
6x + 6y = 540\(^o\)
6(x + y) = 540\(^o\)
x + y = \(\frac{540^o}{6}\) = 90\(^o\)
y = 90\(^o\)
y = 90 - x