If a rod 10cm in length was measured as 10.5cm, calculate the percentage error
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Correct Answer: Option A
Explanation:
Actual measurement = 10cm
approximated value of measurement = 10.5cm
% error = \(\frac{\text{Actual measurement Approximated}}{\text{Actual measure}}\) 100
= \(\frac{10 10.5}{10}\) 100
= \(\frac{-0.5}{10}\) 100
ignore -sign i.e take absolute value
= \(\frac{0.5}{10}\) 100
= 5 %
Actual measurement = 10cm
approximated value of measurement = 10.5cm
% error = \(\frac{\text{Actual measurement Approximated}}{\text{Actual measure}}\) 100
= \(\frac{10 10.5}{10}\) 100
= \(\frac{-0.5}{10}\) 100
ignore -sign i.e take absolute value
= \(\frac{0.5}{10}\) 100
= 5 %