A cone with the sector angle of 45° is cut out of a circle of radius r of the cone.
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Correct Answer: Option C
Explanation:
The formula for the base radius of a cone formed from the sector of a circle = \(\frac{r \theta}{360°}\)
= \(\frac{r \times 45°}{360°}\)
= \(\frac{r}{8} cm\)
The formula for the base radius of a cone formed from the sector of a circle = \(\frac{r \theta}{360°}\)
= \(\frac{r \times 45°}{360°}\)
= \(\frac{r}{8} cm\)