The angle of elevation of a building from a measuring instrument placed on the ground is 30o. If the building is 40m high, how far is the instrument from the foot of the building?
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Correct Answer: Option D
Explanation:
\(\frac{40}{x}\) = tan 30o
x = \(\frac{40}{tan 36}\)
= \(\frac{40}{1\sqrt{3}}\)
= 40√3m
\(\frac{40}{x}\) = tan 30o
x = \(\frac{40}{tan 36}\)
= \(\frac{40}{1\sqrt{3}}\)
= 40√3m